Math, asked by Ashwadi, 1 year ago

If x =7+4√3 then evaluate i) √x+1/√x ii)x^2+1/x^2

Answers

Answered by ShresthaTheMetalGuy
0

Answer:

x=7+4√3

(i)  \frac{ \sqrt{x}  + 1}{ \sqrt{x} }  =  \frac{3 +  \sqrt{3} }{2 +  \sqrt{3} }  = 3 -  \sqrt{3}

(i) Answer: 3–√3

.

(ii) \frac{x {}^{2}  + 1}{x {}^{2} }  = 98 - 56 \sqrt{3}

(ii) 98–56√3

Answered by XxRedmanherexX
0

Answer:

x=7+4√3 \\ </p><p></p><p>(i) \frac{ \sqrt{x} + 1}{ \sqrt{x} } = \frac{3 + \sqrt{3} }{2 + \sqrt{3} } = 3 - \sqrt{3} \\ </p><p></p><p> \\ </p><p></p><p></p><p>(ii) \frac{x {}^{2} + 1}{x {}^{2} } = 98 - 56 </p><p></p><p></p><p>

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