Question

If x =7+4√3 then evaluate i) √x+1/√x ii)x^2+1/x^2

Answer 1

Answer:

x=7+4√3

$(i) \frac{ \sqrt{x} + 1}{ \sqrt{x} } = \frac{3 + \sqrt{3} }{2 + \sqrt{3} } = 3 - \sqrt{3}$

(i) Answer: 3–√3

.

$(ii) \frac{x {}^{2} + 1}{x {}^{2} } = 98 - 56 \sqrt{3}$

(ii) 98–56√3

Answer 2

Answer:

$x=7+4√3 \\ </p><p></p><p>(i) \frac{ \sqrt{x} + 1}{ \sqrt{x} } = \frac{3 + \sqrt{3} }{2 + \sqrt{3} } = 3 - \sqrt{3} \\ </p><p></p><p> \\ </p><p></p><p></p><p>(ii) \frac{x {}^{2} + 1}{x {}^{2} } = 98 - 56 </p><p></p><p></p><p>$