Question

if x=7+4root3,find the value of rootX + 1/rootX

Answer 1

$\sqrt{7 + 4 \sqrt{3} } = \sqrt{7 + 2 \sqrt{12} } = \sqrt{3 + 4 + 2 \sqrt{3 \times 4} } = \sqrt{3} + \sqrt{4} = 2 + \sqrt{3}$
$\sqrt{x} = 2 + \sqrt{3 } \\ \frac{1}{ \sqrt{x} } = \frac{1}{2 + \sqrt{3} } = \frac{2 - \sqrt{3} }{4 - 3} = 2 - \sqrt{3}$
Therefore,
$\sqrt{x} + \frac{1}{ \sqrt{x} } = 2 + \sqrt{3} + 2 - \sqrt{3 } = 4$
The answer is 4

Answer 2

Answer:

hi bhaiyya bhul gaye kya