If x = √7 + √5 and y = √7 - √5, evaluate
i. xy
ii. x^2+y^2
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hey here is ur answer
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see the attachment above
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Given That :- x = √7 + √5 & y = √7 - √5
To Find : ( i ) xy & ( ii ) x² + y²
Solution :
( i ) xy
→ xy = ( √7 + √5 ) ( √7 - √5 )
We know that ( a + b ) ( a - b ) = a² - b²
So,
= ( √7 )² - ( √5 )²
= 7 - 5
= 2
( ii ) x² + y²
→ x² + y² = ( √7 + √5 )² + ( √7 - √5 )²
We know that ( a + b )² = a² + 2ab + b² and ( a - b )² = a² - 2ab + b²
Therefore,
( √7 + √5 )² + ( √7 - √5 )²
= [ ( √7 )² + ( 2 × √7 × √5 ) + ( √5 )² ] + [ ( √7 )² - ( 2 × √7 × √5 ) + ( √5 )² ]
= 7 + 2√35 + 5 + 7 - 2√35 + 5
= 24
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