Question

one side of a triangle is produced and the exterior angles so formed is 120 degree if the interior opposite angles be in the ratio 3 :
5 find the measure of each angle of a triangle

Answer 1

Exterior angle = sum of opposite angles

Solve x:

Given that the ratio is 3 : 5

Let x be the constant ration

3x + 5x = 120

8x = 120

x = 15

Find the angles:

3x = 3(15) = 45°

5x = 5(15) 75°

Answer: The two angles are 45° and 75°

Answer 2

Step-by-step explanation:

the exterior angle is 120°

let x be the constant ratio

By The Problem

3x +5x=120

8x=120

x=120÷8

x=15

the two angles of the ∆is

3x

3×15

45

5x

5×15

75

thus the sides of the triangle are 75°and 45°(ans )