If x=7+root(40) ,find the value of root(x)+1/root(x)
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x = 7 + √40
x = 7 + 2√10
= (√5)^2 + (√2)^2 + 2√(5*2)
= (√5 + √2)^2
√x = √5+√2
1/√x = 1/(√5+√2)
1/√x = (√5 - √2) / 3
√x + 1/√x = (3√5 + 3√2 + √5 - √2) / 3
√x + 1/√x = (4√5 + 2√2) / 3
x = 7 + 2√10
= (√5)^2 + (√2)^2 + 2√(5*2)
= (√5 + √2)^2
√x = √5+√2
1/√x = 1/(√5+√2)
1/√x = (√5 - √2) / 3
√x + 1/√x = (3√5 + 3√2 + √5 - √2) / 3
√x + 1/√x = (4√5 + 2√2) / 3
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