two adjecent angles of a paralleogram are the ratio 4:5 find the measure of each of its angles
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let the common factor be x so..one angle be 4x and other be 5x...now we also know that in parallelogram the opposite angles are equal so...the angles are...4x,4x,5x,5x..so by the angle sum property of a quadrilateral...4x+4x+5x+5x = 360 => 18x = 360=> x=360/18 = 20..so the angles are...20*4=80cm..20*5 =100..angles of the parallelogram are...100cm,100cm,80cm and 80cm
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The ratio is 4:5.
Sum of ratios = 9
therefore smaller angle=angleA = 4/9*180=80degrees
larger angle =angleB= 5/9*180degree= 100degrees
Therefore, angleA=angleC= 80 degrees
angleB=angleC= 100degrees.
(In a parallelogram, opposite angles are equal.)
Sum of ratios = 9
therefore smaller angle=angleA = 4/9*180=80degrees
larger angle =angleB= 5/9*180degree= 100degrees
Therefore, angleA=angleC= 80 degrees
angleB=angleC= 100degrees.
(In a parallelogram, opposite angles are equal.)
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