Question

if x=7 y=4 then value of x
$x3 + y3 \div x2 - xy + y2$


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Answer 1

⠀⠀⠀⠀⠀⠀⠀⠀$\blue\dag$$\red{\bf{Given\:࿐}}$$\blue\dag$

⠀⠀⠀⠀⠀⠀⠀$\sf{The\: value \:of \:x\: =\: 7}$

⠀⠀⠀⠀⠀⠀⠀$\sf{The \:value \:of y\: =\: 4}$

$~~~\blue\dag\red{\bf{Required\:to\:find\:the\:value\:of\:࿐}}\blue\dag$

⠀⠀⠀⠀⠀⠀$~~~~\sf{x^3 + y^3 \div x^2 - xy + y^2}$

$~~~~~~~~~~~~~~~~~~~\blue\dag{\red{\bf{Verification\:࿐}}}$$\blue\dag$

⠀⠀⠀⠀⠀⠀$:\Rightarrow\sf{x^3 + y^3 \div x^2 - xy + y^2}$

$~~~~~~~~~~~~~~~~:\Rightarrow\sf{7^3+4^3\div7^2-7×4+4^2}$

$~~~~~~~~~~~~~{\boxed{\cal{\blue{According\: to\: BODMAS}}}}$

⠀⠀⠀⠀$:\Rightarrow {343+64\div49-28+16}$

⠀⠀⠀⠀⠀⠀$:\Rightarrow {343+1.3-12}$

⠀⠀⠀⠀⠀⠀⠀$:\Rightarrow {244.3-12}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀$:\Rightarrow {332.3}$

______________________________

$\blue{\sf{hope\:it\:helps\:you}}$

Answer 2

Answer:

$\sf{Explanation\:Required\:}\red\checkmark$

$\frac{{x}^{3} + {y}^{3} }{ {x}^{2} - xy + {y}^{2} }$

$\frac{{7}^{3} + {4}^{3} }{ {7}^{2} - 7 \times 4 + {4}^{2} }$

$\frac{343 + 64}{49 - 28 + 16}$

$\frac{407}{37}$

$\frac{ \cancel407}{ \cancel37}$

$= 11$