Math, asked by adeb, 3 months ago

If x=8+3√2 so find the value of x^3/x^6-3x^2+1​

Answers

Answered by rofessordebbarma
0

Answer:

1/431 + 27√2

Step-by-step explanation:

x=8+3√2

So,

x^3/x^6-3x^2+1

= (8+3√2)^3/(8+3√2)^6 - (8+3√2)^2 + 1

= 1/(8+3√2)^3 - 64 - 18 + 1

= 1/512 + 27√2 - 64 - 18 + 1

= 1/431 + 27√2

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