If x=8 find the value of the polynomial p(x)=xsquire+x-5
Answers
Answer:
67
Step-by-step explanation:
Answer:
Find the values of p and q so that x
4
+x
3
+8x
2
−px+q is divisible by x
2
+1.
Study later
View solution
Step-by-step explanation:
If α
If α1
If α1
If α1 ,α
If α1 ,α2
If α1 ,α2
If α1 ,α2 , α
If α1 ,α2 , α3
If α1 ,α2 , α3
If α1 ,α2 , α3 ,⋯ α
If α1 ,α2 , α3 ,⋯ αn
If α1 ,α2 , α3 ,⋯ αn
If α1 ,α2 , α3 ,⋯ αn are the roots of the equation (x−β
If α1 ,α2 , α3 ,⋯ αn are the roots of the equation (x−β1
If α1 ,α2 , α3 ,⋯ αn are the roots of the equation (x−β1
If α1 ,α2 , α3 ,⋯ αn are the roots of the equation (x−β1 )(x−β
If α1 ,α2 , α3 ,⋯ αn are the roots of the equation (x−β1 )(x−β2
If α1 ,α2 , α3 ,⋯ αn are the roots of the equation (x−β1 )(x−β2
If α1 ,α2 , α3 ,⋯ αn are the roots of the equation (x−β1 )(x−β2 )⋯…(x−β
If α1 ,α2 , α3 ,⋯ αn are the roots of the equation (x−β1 )(x−β2 )⋯…(x−βn
If α1 ,α2 , α3 ,⋯ αn are the roots of the equation (x−β1 )(x−β2 )⋯…(x−βn
If α1 ,α2 , α3 ,⋯ αn are the roots of the equation (x−β1 )(x−β2 )⋯…(x−βn )=A and if the equation having β
If α1 ,α2 , α3 ,⋯ αn are the roots of the equation (x−β1 )(x−β2 )⋯…(x−βn )=A and if the equation having β1
If α1 ,α2 , α3 ,⋯ αn are the roots of the equation (x−β1 )(x−β2 )⋯…(x−βn )=A and if the equation having β1
If α1 ,α2 , α3 ,⋯ αn are the roots of the equation (x−β1 )(x−β2 )⋯…(x−βn )=A and if the equation having β1 , β
If α1 ,α2 , α3 ,⋯ αn are the roots of the equation (x−β1 )(x−β2 )⋯…(x−βn )=A and if the equation having β1 , β2
If α1 ,α2 , α3 ,⋯ αn are the roots of the equation (x−β1 )(x−β2 )⋯…(x−βn )=A and if the equation having β1 , β2
If α1 ,α2 , α3 ,⋯ αn are the roots of the equation (x−β1 )(x−β2 )⋯…(x−βn )=A and if the equation having β1 , β2 , β
If α1 ,α2 , α3 ,⋯ αn are the roots of the equation (x−β1 )(x−β2 )⋯…(x−βn )=A and if the equation having β1 , β2 , β3
If α1 ,α2 , α3 ,⋯ αn are the roots of the equation (x−β1 )(x−β2 )⋯…(x−βn )=A and if the equation having β1 , β2 , β3
If α1 ,α2 , α3 ,⋯ αn are the roots of the equation (x−β1 )(x−β2 )⋯…(x−βn )=A and if the equation having β1 , β2 , β3 , β
If α1 ,α2 , α3 ,⋯ αn are the roots of the equation (x−β1 )(x−β2 )⋯…(x−βn )=A and if the equation having β1 , β2 , β3 , βn
If α1 ,α2 , α3 ,⋯ αn are the roots of the equation (x−β1 )(x−β2 )⋯…(x−βn )=A and if the equation having β1 , β2 , β3 , βn
If α1 ,α2 , α3 ,⋯ αn are the roots of the equation (x−β1 )(x−β2 )⋯…(x−βn )=A and if the equation having β1 , β2 , β3 , βn as the roots is (x−α
If α1 ,α2 , α3 ,⋯ αn are the roots of the equation (x−β1 )(x−β2 )⋯…(x−βn )=A and if the equation having β1 , β2 , β3 , βn as the roots is (x−α1
If α1 ,α2 , α3 ,⋯ αn are the roots of the equation (x−β1 )(x−β2 )⋯…(x−βn )=A and if the equation having β1 , β2 , β3 , βn as the roots is (x−α1
If α1 ,α2 , α3 ,⋯ αn are the roots of the equation (x−β1 )(x−β2 )⋯…(x−βn )=A and if the equation having β1 , β2 , β3 , βn as the roots is (x−α1 )(x−α
If α1 ,α2 , α3 ,⋯ αn are the roots of the equation (x−β1 )(x−β2 )⋯…(x−βn )=A and if the equation having β1 , β2 , β3 , βn as the roots is (x−α1 )(x−α2
If α1 ,α2 , α3 ,⋯ αn are the roots of the equation (x−β1 )(x−β2 )⋯…(x−βn )=A and if the equation having β1 , β2 , β3 , βn as the roots is (x−α1 )(x−α2
If α1 ,α2 , α3 ,⋯ αn are the roots of the equation (x−β1 )(x−β2 )⋯…(x−βn )=A and if the equation having β1 , β2 , β3 , βn as the roots is (x−α1 )(x−α2 )………(x−α
If α1 ,α2 , α3 ,⋯ αn are the roots of the equation (x−β1 )(x−β2 )⋯…(x−βn )=A and if the equation having β1 , β2 , β3 , βn as the roots is (x−α1 )(x−α2 )………(x−αn
If α1 ,α2 , α3 ,⋯ αn are the roots of the equation (x−β1 )(x−β2 )⋯…(x−βn )=A and if the equation having β1 , β2 , β3 , βn as the roots is (x−α1 )(x−α2 )………(x−αn
If α1 ,α2 , α3 ,⋯ αn are the roots of the equation (x−β1 )(x−β2 )⋯…(x−βn )=A and if the equation having β1 , β2 , β3 , βn as the roots is (x−α1 )(x−α2 )………(x−αn )=k, then k=
If α1 ,α2 , α3 ,⋯ αn are the roots of the equation (x−β1 )(x−β2 )⋯…(x−βn )=A and if the equation having β1 , β2 , β3 , βn as the roots is (x−α1 )(x−α2 )………(x−αn )=k, then k=Study later
View solution