Question

If x=8 is one root of the quadratic equation x²-2kx-6=0 then find value ok k.​

Answer 1

Explanation:

Let

p(x) = x²-2kx-6=0

x= 8 is one root of the quadratic equation

Remainder = p(8) = 0

=> p(8)=0

=> (8)²-2k(8) - 6 = 0

=> 64-16k-6=0

=> -16k=6-64

=> - 16k = -58

=> k=58/16

=> k=29/8

Answer 2

Answer:

x² -2kx-6=0

(8) -2k(8) - 6 =0

64 -16k -6 =0

58-6-16k =0

k =58/16

k = 29/8

Explanation:

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