if x=8a-3b+11c,y=5b-6a+7c and z=9c+2a-8b then x+y+z
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Answered by
3
x+y+z=8a-6a+2a-3b+5b-8b+11c+7c+9c
=4a-6b+27c
=4a-6b+27c
Answered by
5
hello users ...
Given that:
x=8a - 3b + 11c,
y=5b - 6a + 7c
and
z=9c + 2a - 8b
solution:-
Here
x + y + z = (8a - 3b + 11c) + (5b - 6a + 7c) + (9c + 2a - 8b)
= [ 8a - 3b + 11c + 5b - 6a + 7c + 9c + 2a - 8b ]
= [ (8a - 6a + 2a ) + ( 5b - 3b - 8b) + (11c + 7c +9c) ]
= ( 4a - 6b + 27c ) Answer
# hope it helps :)
Given that:
x=8a - 3b + 11c,
y=5b - 6a + 7c
and
z=9c + 2a - 8b
solution:-
Here
x + y + z = (8a - 3b + 11c) + (5b - 6a + 7c) + (9c + 2a - 8b)
= [ 8a - 3b + 11c + 5b - 6a + 7c + 9c + 2a - 8b ]
= [ (8a - 6a + 2a ) + ( 5b - 3b - 8b) + (11c + 7c +9c) ]
= ( 4a - 6b + 27c ) Answer
# hope it helps :)
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