Question

prove that root p + root q is irrational​

Answer 1

Answer:

Let √p + √q = a, where a is rational. => √p = (a2 + p - q)/2a, which is a contradiction as the right hand side is rational number, while√p is irrational. Hence, √p + √q is irrational.

Step-by-step explanation:

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Answer 2

Let √p + √q = a, where a is rational. => √p = (a2 + p - q)/2a, which is a contradiction as the right hand side is rational number, while√p is irrational. Hence, √p + √q is irrational.