If x= 9-4√5 :
find
(a). √x -1/√x
(b). x -1/x
Answers
Answered by
0
Answer:
If x= 9-4√5 :
find
(a). √x -1/√x
(b). x -1/x
Attachments:
Answered by
0
ANSWERS = a => 16 b=> 0
x = 9 - 4√5
a) (√x - ( 1/√x))^2 = √x ^2 - (2.√x.1 / √x ) +( 1 / √x)^2
= x + (1 / x) - 2
x + 1/x = 9 - 4√5 + ( 1 / 9 - 4√5)-2
= 9 - 4√5 + [( 9 + 4√5 )/ (9 ^2 - (4√5)^2) ]-2
= 9 - 4√5 + [( 9 + 4√5) / (81 - 80)] - 2
= 9 - 4 √5 + 9 + 4√5 - 2
= 18 -2
= 16
b) x - (1/x) = 9 - 4√5 - ( 1/ 9 -/4√5)
= 9 - 4√5 - [ 9+ 4√5/ (9^2 - (4√5)^2)]
= 9 - 4√5 - [ (9 + 4√5) / (81 - 80)]
= 9 - 4√5 - 9 - 4√5
= 0
Similar questions