if x=9-4√5,then find the value of x^2+1/x^2
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Answered by
40
x=9-4√5
1 = 1
x 9-4√5
Rationalising the equation
1 = 1 × 9+4√5
x 9-4√5 9+4√5
1 = 9+4√5
x 81-80
1 = 9+4√5
x
x²=(9-4√5)² = 81+80 - 72√5
1 = (9+4√5)²= 81+80+72√5
x²
x²+1/x² = 161-72√5+161+72√5
x²+1/x² = 161+161
x²+1/x²=322
1 = 1
x 9-4√5
Rationalising the equation
1 = 1 × 9+4√5
x 9-4√5 9+4√5
1 = 9+4√5
x 81-80
1 = 9+4√5
x
x²=(9-4√5)² = 81+80 - 72√5
1 = (9+4√5)²= 81+80+72√5
x²
x²+1/x² = 161-72√5+161+72√5
x²+1/x² = 161+161
x²+1/x²=322
Answered by
31
so given x = 9 - 4√5
1/x = 1/(9 - 4√5)
= 9 + 4√5 after rationalizing
so we know (a+b)² + (a-b)² = 2(a² + b²)
so substituting the values
= 2(81 + 80)
= 2 x 161 = 322 ANSWER
1/x = 1/(9 - 4√5)
= 9 + 4√5 after rationalizing
so we know (a+b)² + (a-b)² = 2(a² + b²)
so substituting the values
= 2(81 + 80)
= 2 x 161 = 322 ANSWER
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