If x=9+4 root 5 then find root x-1/root x
Answers
Answered by
2
Solution :
x = 9 + 4√5
= 9 + 2√4×5
= 5 + 4 + 2•√4•√5
= (√5)²+(√4)²+2•√4•√5
= (√5 + √4 )²
= (√5 + 2 )²
i ) √x = √(√5 + 2)²
= √5 + 2 ----( 1 )
ii ) 1/√x = 1/(√5 + 2 )
= (√5 -2 )/[(√5+2)(√5-2)]
= (√5-2)/( 5 - 4 )
= √5 - 2 ---( 2 )
Now ,
√x - 1/√x
= √5 + 2 - ( √5 - 2 )
= √5 + 2 - √5 + 2
= 4
Or
2√5
••••
x = 9 + 4√5
= 9 + 2√4×5
= 5 + 4 + 2•√4•√5
= (√5)²+(√4)²+2•√4•√5
= (√5 + √4 )²
= (√5 + 2 )²
i ) √x = √(√5 + 2)²
= √5 + 2 ----( 1 )
ii ) 1/√x = 1/(√5 + 2 )
= (√5 -2 )/[(√5+2)(√5-2)]
= (√5-2)/( 5 - 4 )
= √5 - 2 ---( 2 )
Now ,
√x - 1/√x
= √5 + 2 - ( √5 - 2 )
= √5 + 2 - √5 + 2
= 4
Or
2√5
••••
nishantinferno:
It's root x-1/root x
Answered by
1
Answer:
18
Step-by-step explanation:
1 / x = 1 / ( 9 + 4√5 )
= ( 9 - 4√5 ) / ( 9² - (4√5)² ) (multiplied numerator and denominator by conjugate)
= ( 9 - 4√5 ) / ( 81 - 80 )
= 9 - 4√5
So x - 1 / x = ( 9 + 4√5 ) - ( 9 - 4√5 ) = 8√5
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