If x“ = (a + 2)", (where 'a' is odd), then x - a =
a) 0
b) 1
d) 2
c) a - 2
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Answer:
Let x=2k+1∈Z be odd. So,
x2=(2k+1)2=4k2+4k+1=2(2k2+2k)+1
Let t=2k2+2k∈Z, thus: x2=2t+1.
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