If x=a+b-c, y=b+c-a, z= -2b then x^3 + y^3 +z^3 is equal to:
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Solution:
/* we know that,
If x+y+z=0 then
x³+y³+z³ = 3xyz */
Here ,
x = a+b-c ,
y = b+c-a,
z = -2b
Now ,
x+y+z
= a+b-c+b+c-a-2b
= 0
Therefore,
x³+y³+z³
= 3xyz
= 3(a+b-c)(b+c)(-2b)
= -6b(b+c)(a+b-c)
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