Question

if x=a-b, y=b-c, z=c-a, find the value of zx-3y-4z​

Answer 1

Answer:

(a-b) (c-a) -3(b-c) -4(c-a)

=ac-a^2-bc+ba-3b+3c-4c+4a

=a^2-bc+ac+ab-3b-c+4a

Answer 2

It is given that x=a-b, y=b-c, z=c-a and that we have to find the value of zx-3y-4z.

So, now on putting the values, we get:-

=zx-3y-4z

=(c-a)(a-b)-3(b-c)-4(c-a)

=ca-cb-a²+ab-3b+3c-4c+4a

=ca-cb-a²+ab-3b-c+4a

This is the answer.

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