If x=a cos 0 and y=bsin 0, then the value of b^2x^2+a^2y^2 is
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Answered by
0
Answer:
x=acosθ;y=bsinθ
cosθ=
a
x
;sinθ=
b
y
cos
2
θ+sin
2
θ=1=
a
2
x
2
+
b
2
y
2
x
2
b
2
+a
2
y
2
=a
2
b
2
.
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