If (x/a)cos alpha+(y/b)sin alpha=1,(x÷a)cos beta+(y/b)sin beta=1 and cos alpha×cos beta/a^2+sin alpha×sin beta/b^2=0 then prove that tan alpha×tan beta=b^2(x^2-a^2)/a^2(y^2-b^2) and x^2+y^2=a^2-b^2
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