If x = a Cosθ, y = b sinθ, then b2x2 + a2y2 – a2b2 is equal to?
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The answer is zero
first u square both sides on the two eqns
x = a Cosθ , y = b sinθ and but value of x2 and y2 in :
b2x2 + a2y2 – a2b2
and then take a2b2 common u will get the answer
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