IF X=A COS∅, Y=B SIN∅ THEN FIND THE VALE OF B²X²+A²Y²-A²B².
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X=A COSØ Y= B SINØ
COSØ = X\A. SINØ = Y\B
SIN²Ø + COS²Ø = 1
X²\A² + Y²\B² = 1
B²X² + A²Y²\ A²B² = 1
B²X² + A²Y² = A²B²
B²X² + A²Y²- A²B² = 0 (ANS.)
COSØ = X\A. SINØ = Y\B
SIN²Ø + COS²Ø = 1
X²\A² + Y²\B² = 1
B²X² + A²Y²\ A²B² = 1
B²X² + A²Y² = A²B²
B²X² + A²Y²- A²B² = 0 (ANS.)
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