Math, asked by aasthashrivastava, 1 year ago

if x/a cos°+y/b sin°=1 and x/a sin°-y/b cos°=1prove that x*x/a*a+y*y/b*b=1

Answers

Answered by Agnishupadhyay
5
For simplicity I am not writing Theta or other variable.
THE ANSWER WILL BE 2 , NOT 1 
x/acos + y/bsin = 1
x/asin  -  y/bcos = 1
Square both 
x^2/a^2 cos^2 + y^2/b^2sin^2 + 2xy/absincos=1
x^2/a^2 sin^2 + y^2/b^2cos^2 - 2xy/absincos=1
  NOW ADD BOTH 
x^2/a^2(sin^2 + cos^2) + y^2/b^2(sin^2 + cos^2) = 2
sin^2 + cos^2 = 1
So , x^2/a^2 + y^2/b^2 = 2
Answered by broke
7
Hey

Here is ur answer

Hope it helps you
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