If (x +a ) ia a factor of 2xsquare + 2ax +5x + 10 ,find a
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we put x+a=0
x+a=0
x=-a
we put x=-a in the p(x)
2(-a)^2 + 2×a×-a +5×-a + 10=0 (2a)^2 -(2a)^2 -5a + 10 = 0
-5a+10=0
-5a=-10
a=10/5
a=2
Thus, we can find the value of a=2 in this method also.
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