Question

If x+a is a common factor 0f x2+px+q and x2+mx+n, prove that a=n-q/p-m.​

Answer 1

Answer

(-a)² + p·(-a) + q = 0 --> a² -ap + q = 0 

(-a)² + m·(-a) + n = 0 --> a² -am + n = 0 

Since they both equal 0, you can set them equal to each other: 

a² -ap + q = a² -am + n 

-ap + q + -am + n 

am - ap = n-q 

a(m-p) = n-q 

Answer 2

Answer:

Hope this helps you ✌️✌️