If x+a is a factor of 2x2+2ax+5x+10 find a zero of the polynomial
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Let f(x)=2x^2+2ax+5x+10. If x+a is a factor f (-a)=0 f (- a)=2*((-a)^2)+2*a*(- a)+5*(-a)+10=0 2(a)^2-2(a)^2-5a+10=0
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Answer:
-5/2
Step-by-step explanation:
- x+a=0
∴ x = -a
p(a)= 2(-a)²+2a×(-a)+5×(-a)+10=0
=2a²-2a²-5a+10=0
=-5a+10=0
∴a=2
p[x]=2x²+4x+5x+10
=2x²+9x+10
2x²+9x+10/x+2=2x+5
2x+5=0
x=-5/2
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