If two forces in the ratio5:9 act on two areas 10:3 find the area of pressure exerted
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Let the two forces be 5x and 9x respectively.
And let the two areas be 10y and 3y respectively.
1st case:-
Pressure = 5x/10y = x/2y
2nd case:-
Pressure = 9x/3y = 3x/y
Ratio of both the pressures respectively = (x/2y) / (3x/y) = 1:6
Thus, the required solution is 1:6.
And let the two areas be 10y and 3y respectively.
1st case:-
Pressure = 5x/10y = x/2y
2nd case:-
Pressure = 9x/3y = 3x/y
Ratio of both the pressures respectively = (x/2y) / (3x/y) = 1:6
Thus, the required solution is 1:6.
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