Question

If x + a is a factor of 3x² - mx - nx prove that a = m+n/3

Answer 1

Answer:

a=(m+n) /3

Step-by-step explanation:

F(x) =3x²-mx-nx

G(x) =x-a

It is given that F(x) is divisible by G(x), thus from remainder their

F(a) =0

3a²-ma-na=0

3a²=ma+na

3a²=a(m+n)

Dividing by a on both sides

3a=m+n

a=(m+n) /3.

Hence proved

Answer 2

Answer:

F(x) =3x²-mx-nx

G(x) =x-a

From remainder theorem,

3a²-ma-na=0

3a²=ma+na

3a²=a(m+n)

Dividing by a on both sides

3a=m+n

a=(m+n) /3.

HOPE IT HELPS YOU

PLEASE MARK ME AS THE BRAINLIEST