Question

if x-a is a factor of x^8-ax^7+x^6-ax^5+x^4-ax^3+3ax-a+2​

Answer 1

Answer:

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Answer 2

x-a is a factor of x^{6}-ax^{5}+x^{4}-ax^{3}+3x-a+2 .

Here, the degree of polynomial is = 6.So, this polynomial has 6 roots.

P(a) = 0 ( If we insert a in place of x we get 0 remainder , because a factor completely divides it divident )

x-a = 0

x = a

Now,

Insert x at the place of a.

so,

x^{6}-ax^{5}+x^{4}-ax^{3}+3x-x+2 = 0

x^{6}-x^{6}+x^{4}-x^{4}+3x-x+2 = 0

2a - 2 = 0

2a = 2

a = \frac{2}{2}

a = 1