Question

If x-a is a factor of x-ax +2x+a-1, find the value of a.
Using proper identities, factorise the following

Please answer fast.

I will mark as brainiest to the first and accurate answer.​

Answer 1

Answer:

Step-by-step explanation:

If x-a is a factor

then x-a=0 will be zero of the polynomial

x-a=0

x=a

Let take this polynomial as p(x)

P(x)=x-ax+2x+a-1

p(a)=a-(a^2)+2a+a-1

(-a^2-1)=0 by factor theoram

-a^2=1

a^2=1(as - will cancel each other)

a=Root(1)

a=1

Answer 2

[x-a]=x-ax+2x+a-1

finding the value of x

x-a=0

x=a

plotting the value in place of x.

[a]-a[a]+2[a]+a-1=0

a-a²+2a+a-1=0

3a+a-a²-1=0

4a-a²-1=0

4a-a²=1

4a-a=√1

3a=1   [√1=1]

a=1/3