Math, asked by kajalanandkumarsingh, 1 day ago

If x-a is a factor of x3 - 3x²a + 2a²x + b, then the find value of b. -​

Answers

Answered by Mysteryboy01
1

 =  {x}^{3}  - 3 {x}^{2} a  + 2 {a}^{2} x + b

x - a = 0

x = a

 =  {a}^{3}  - 3( {a)}^{2}  + 2( {a)}^{2}  + b

 =  {a}^{3}  - 3 {a}^{2}  + 2 {a}^{2}  + b

 =  {a}^{3}  -  {a}^{2}   + b

 =  {a}^{2} (a  - 1 + b)

 = a - 1 + b

 - b =  - a + 1

b = a + 1

Answered by ՏʍɑɾեíҽƓմɾƖ
1

Answer:

Let f (x) = x³ - 3x²a + 2a²x + b

Since, x - a is a factor of f(x) then, f (a) = 0

⇒ a³ - 3a²a + 2a²a + b = 0  

⇒ a³ - 3a³ + 2a³ + b = 0  

⇒ -  2a³ + 2a³ + b = 0  

⇒ b = 0

Hence, the value of b is 0.

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