Math, asked by uditagharde, 1 day ago

If (x-a) is a factor of (x3-ax2+2x+a-1), find the value of a​

Answers

Answered by rockj292004
1

Answer:

(x-a) is the factor of given equation

thus

x=a

thus

x³-ax²+2x+a-1=0

a³-a³+2a+a-1=0

3a-1=0

a=1/3

Answered by enricheducater
0

Answer:

a=1/3

Step-by-step explanation:

if x-a is a factor, then, x=a

p(x)= a^3-a*a^2+2aa-1

=a^3-a^3+2a+a-1= 3a-1

3a-1=0

3a=1

a=1/3

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