Question

If x = a sec 0 and y = b tan 0 then x² - y^2 =​

Answer 1

Answer:

let A = theta

x² - y² = a² sec² A + b² tan² A + 2 ab secA tan A

- (a² tan² A + b² sec²A + 2ab tanA secA)

= a² (sec²A - tan²A) + b² (sec²A - tan²A)

= a² - b²