Question

solve this equation 54nq-108n^2+70n=420​

Answer 1

Answer: 54n(-2n+q)+70(n-6)

Step-by-step explanation:

Rearrange the given equation inform of:

ax^2+bxy+c=0, where a,b and c are constants.

-108n^2+54nq+70n-420=0

54n(-2n+q)+70(n-6)

Answer 2

Answer:

54n(q - 2n) + 70(n-6) = 0

Step-by-step explanation:

In this question,

We have to solve this equation,

$54nq - 108n^{2} + 70n = 420$

Therefore, According to the question,

$-108n^{2} + 54nq + 70n - 420 = 0$

54n(q - 2n) + 70(n - 6) = 0

So, the simplified form of $54nq - 108n^{2} + 70n = 420$

is 54n(q - 2n) + 70(n-6) = 0

Answer =  54n(q - 2n) + 70(n-6) = 0