Question

If x= a sec Φ and y= b tan Φ then show that b² x²- a²y²= a²b²​

Answer 1

If x= a sec Φ and y= b tan Φ then show that b² x²- a²y²= a²b²​

b²(a sec Φ)² - a² (b tanΦ )²

= b² a²  sec² Φ - a²  b² tan² Φ  

= b² a²  ( sec²Φ - tan² Φ)

= b² a²                                                             as  sec²Φ - tan² Φ= 1

Equal to RHS

Hence shown

Mark as brainliest if it helped:D