Question

If x = a secθ and y = btanθ, then prove that x^2/a^2–y^2/b^2= 1.

Answer 1

Answer:

x^2 = a^2 sec^2θ

y^2 = b^2 tan^2θ

x^2/a^2 - y^2/b^2 = sec^2θ - tan^2θ = 1

Answer 2

Answer:

the solution is In the above image