Question

If X=a sec U and y=B tan U prove that b^2x^2-a^2y^2=a^2b^2?
Please answer me some one it's urgent

Answer 1

:

let A = theta

x² - y² = a² sec² A + b² tan² A + 2 ab secA tan A

                 - (a² tan² A + b² sec²A + 2ab tanA secA)

         = a² (sec²A - tan²A) + b² (sec²A - tan²A)

         = a² - b²