Question

in a quadrilateral ABCD, there is a point o inside it such that OB=OD also, AB=AD and BC=DC. prove that o lies AC.

Answer 1

Answer:

Step-by-step explanation:BD < 10 ( as the sum of any 2 sides of a triangle > third side)

Had it been 10 , < BAD would be 60°

But since 0 < BD < 10

So, without having been given any more information about the quadrilateral, < BAD can hold any unique value. Angle BAD lies between 0° to 60°

0° < angle BAD < 60°

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