If x=a sin t and y=b tan t, prove that a^2/x^2 -b^2/y^2=1
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x= a.sint y=b.tant
prove that a^2/x^2-b^2/y^2=1
= a^2/a^2sin^2t - b^2/b^2tan^t.
=1/sin^2t - cos^2t/sin^2t= 1
hence proved.
prove that a^2/x^2-b^2/y^2=1
= a^2/a^2sin^2t - b^2/b^2tan^t.
=1/sin^2t - cos^2t/sin^2t= 1
hence proved.
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