Question

if x = a sino and y = b tano Prove
that (a²/x²=b²/y²)=1​

Answer 1

Answer :

We have ,

L.H.S = a^2/x^2 - b^2 /y^2

⇒L.H.S = [a^2 ÷ (asinθ)^2] - [ b^2 ÷ (btanθ)^2]

[∵ x = asinθ , y= btanθ ]

⇒L.H.S = (1 ÷ sin ^2θ) - (1 ÷ tan^2θ)

⇒L.H.S = cosec^2 θ − cot^2 θ

[∵1 + cot^2 θ = cosec^2 θ

∴ cosec^2 θ − cot^2 θ = 1 ]

⇒ LHS = 1 = RHS

Answer 2

Answer:

give thanx=take thanks

Step-by-step explanation:

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