If x^a=y^b=z^c and y^3=xz show that 3/b =1/a+1/c
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Step-by-step explanation:
here
x^a=y^b=z^c = k (suppose)
Now,
x^a =k
x = k^1\a
y = k^1/b
z =k^1\c
we know,
y^3 = xz
(k^1\b)^3 = k^1\a × k^1\c
k^3\b= k^(1\a + 1\c)
3/b = 1\a + 1\c
which is proved
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