Question

If x:a=y:b=z:c then show that,
x3/a2 + y3/b2 +z3/c2 =(x+y+z)3/(a+b+c)2

Answer 1

Answer:(x+y+z)^3/(a+b+c)^2

Step-by-step explanation:first take the common factors,that would be x^3,y^3,z^3 in the numerator and a^2,b^2,c^2 in the denominator.