If x and y are real nos. such that 2log(2y-3x)= logx+logy, find x/y.
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Log(2 Y - 3 x) whole square is equal to log( x into y)
4y^2 - 12xy+9x^2 =xy
4y^2 - 13xy+9x^2 =0
(dividing all y square not is equal to zero)
4-13x/y+9(x/y)^2 =0
4=x/y(13-9x/y)
x/y= 4y/13y-9x
4y^2 - 12xy+9x^2 =xy
4y^2 - 13xy+9x^2 =0
(dividing all y square not is equal to zero)
4-13x/y+9(x/y)^2 =0
4=x/y(13-9x/y)
x/y= 4y/13y-9x
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