Question

If x and y are to positive real numbers, find the value of

Answer 1

$\frac{ \sqrt[3]{x {y}^{2} } }{ {x}^{2} y} \\ \\ = \frac{{x}^{ \frac{1}{3} } {y}^{ \frac{2}{3} } }{ {x}^{2} y} \\ \\ = \frac{1}{ \sqrt[3]{ {x}^{5} y} }$

hope it helps