Question

if x and y are two positive real numbers such that 9X square + Y square = 96 and xy=8 then find the value of 3X+Y

Answer 1

9x square+y square=96. xy=8
(3x) square+y square=96
(3x+y)square-6xy=96
(3x+y)square=96+48
(3x+y)square=144
3x+y=12
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