If x and y vary inversely and x=15 when y=6,find y when x=9.
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Answered by
149
x inversely to y
y=k×1/x
xy=k.........(1)
x=15 & y=6
substitute in eqn (1)
15×6=k
90=k
when x=9 put eqn value of k and x
9×y=90
y=90/9
y=10
y=k×1/x
xy=k.........(1)
x=15 & y=6
substitute in eqn (1)
15×6=k
90=k
when x=9 put eqn value of k and x
9×y=90
y=90/9
y=10
Answered by
13
Answer:
If x and y vary inversely and x=15 when y=6, then y= 10 when x=9.
Step-by-step explanation:
Two quantities x, and y, are said to be in inverse proportion if they fulfill the following criteria:
If x increases, there is a decrease in y.
If x decreases, there is an increase in y.
x × y = k (constant K)
If x = 15 and y = 6 then find k
k = x × y
= 15 × 6
k = 90
Now when k = 90, x = 9 find y
k = x × y
9 × y = 90
y= 90/9
y = 10
So, value of y = 10.
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