Question

if x =asec theta and y =btan theta find b^2x^2-a^2y^2

Answer 1

Answer:

as we know the identity

Answer 2

x/a = sec Θ

y/b = tan

x^2/a^2 - y^2/b^2 = 1

(x^2 b^2 - y^2 a^2) / a^2 b^2 = 1

x^2 b^2 - y^2 a^2 = a^2 b^2

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