Physics, asked by ankit1092, 1 month ago

if x=AsinWt then the value of d^2x/dt^2 is ( where A and W are constant) ?​

Answers

Answered by dkchakrabarty01
1

Answer:

Let wt= y, the

dt/dy=1/w

x=Asiny

dx/dy =Acos y

dx/dt)(dt/dy)=Acos y

dx/dt=Aw cos wt

d^2x/dt^2= Aw.w(-sinwt)

=-Aw^2(sinwt)

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