if (x-b-c/a)+(x-a-c/b)+(x-a-c/c)=3 , find value of x
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x-b-c/a +x-a-c/b +x-a-b/c=3
Or, (x-b-c/a -1) +(x-a-c/b - 1)+(x-a-b/c -1)=0
Or, (x-a-b-c)/a +(x-a-b-c)/b+(x-a-b-c)/c=0
Or, (x-a-b-c)(1/a+1/b+1/c)=0
Or, x-a-b-c=0(since 1/a+1/b+1/c not equal to 0)
Or, x=a+b+c
Or, (x-b-c/a -1) +(x-a-c/b - 1)+(x-a-b/c -1)=0
Or, (x-a-b-c)/a +(x-a-b-c)/b+(x-a-b-c)/c=0
Or, (x-a-b-c)(1/a+1/b+1/c)=0
Or, x-a-b-c=0(since 1/a+1/b+1/c not equal to 0)
Or, x=a+b+c
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