Question

If x/b-c=y/c-a=z/a-b,prove that ax + by + cz=0
Please answer this question.

Answer 1

Answer:

Let ax = by = cz = k, then

x = k/a,  y = k/b and z = k/c

L.H.S.  = x2/yz + y2/zx + z2/xy

=  k2/a2 × k/b × k/c + k2/b2 × k/c × k/a + k2/c2 × k/a × k/b

= bc/a2 + ca/b2 + ab/c2

=  R.H.S

Step-by-step explanation: